[머신러닝] 모델 생성 및 평가

 

 

 

 

 

모델 생성 및 평가

5. 모델 생성 및 평가.html

0.30MB

5. 모델 생성 및 평가.ipynb

0.05MB

 

 

 

 

In [1]:

import pandas as pd

In [2]:

df = pd.read_csv("../data_set/2.데이터 클린징/loan_train_quiz_cleaning.csv")
df.head()

Out[2]:

	Loan_ID	Gender	Married	Dependents	Education	Self_Employed	ApplicantIncome	CoapplicantIncome	LoanAmount	Loan_Amount_Term	Credit_History	Property_Area	Loan_Status
0	0	1	0	0	0	0	5849	0.0	128.0	360.0	1.0	2	1
1	1	1	1	1	0	0	4583	1508.0	128.0	360.0	1.0	0	0
2	2	1	1	0	0	1	3000	0.0	66.0	360.0	1.0	2	1
3	3	1	1	0	1	0	2583	2358.0	120.0	360.0	1.0	2	1
4	4	1	0	0	0	0	6000	0.0	141.0	360.0	1.0	2	1

변수¶

• label : 정답, 종속변수
• feature : 속성, 독립변수

In [3]:

df.columns

Out[3]:

Index(['Loan_ID', 'Gender', 'Married', 'Dependents', 'Education',
       'Self_Employed', 'ApplicantIncome', 'CoapplicantIncome', 'LoanAmount',
       'Loan_Amount_Term', 'Credit_History', 'Property_Area', 'Loan_Status'],
      dtype='object')

In [25]:

features = ['Gender', 'Married', 'Dependents', 'Education',
       'Self_Employed', 'ApplicantIncome', 'CoapplicantIncome', 'LoanAmount',
       'Loan_Amount_Term', 'Credit_History', 'Property_Area']
label = 'Loan_Status'
# Loan_Status : 대출이 가능한지 불가능한지 여부

# features 는 결과에 요인을 주는 요소
# label 은 알고자 하는 결과 값
X, y = df[features], df[label]

In [5]:

y

Out[5]:

0      1
1      0
2      1
3      1
4      1
      ..
609    1
610    1
611    1
612    1
613    0
Name: Loan_Status, Length: 614, dtype: int64

In [6]:

X

Out[6]:

	Gender	Married	Dependents	Education	Self_Employed	ApplicantIncome	CoapplicantIncome	LoanAmount	Loan_Amount_Term	Credit_History	Property_Area
0	1	0	0	0	0	5849	0.0	128.0	360.0	1.0	2
1	1	1	1	0	0	4583	1508.0	128.0	360.0	1.0	0
2	1	1	0	0	1	3000	0.0	66.0	360.0	1.0	2
3	1	1	0	1	0	2583	2358.0	120.0	360.0	1.0	2
4	1	0	0	0	0	6000	0.0	141.0	360.0	1.0	2
...	...	...	...	...	...	...	...	...	...	...	...
609	0	0	0	0	0	2900	0.0	71.0	360.0	1.0	0
610	1	1	3	0	0	4106	0.0	40.0	180.0	1.0	0
611	1	1	1	0	0	8072	240.0	253.0	360.0	1.0	2
612	1	1	2	0	0	7583	0.0	187.0	360.0	1.0	2
613	0	0	0	0	1	4583	0.0	133.0	360.0	0.0	1

614 rows × 11 columns

In [8]:

# 전체 데이터 갯수와 컬럼 갯수 확인
df.shape

Out[8]:

(614, 13)

In [9]:

from sklearn.model_selection import train_test_split

In [12]:

# 학습용 데이터로 80% 를 할당
# 검증용 데이터로 20% 를 할당
X_train, X_test, y_train, y_test = train_test_split(X, y, test_size=0.2)

In [11]:

X_train.shape, X_test.shape, len(y_train), len(y_test)

Out[11]:

((491, 11), (123, 11), 491, 123)

In [13]:

# 데이터를 학습 시킨다
# X(요소)일 경우 y(결과) 가 나온다 를 학습 시킨다
from sklearn.tree import DecisionTreeClassifier
dtc = DecisionTreeClassifier()
dtc.fit(X_train, y_train)

Out[13]:

DecisionTreeClassifier()

In a Jupyter environment, please rerun this cell to show the HTML representation or trust the notebook.
On GitHub, the HTML representation is unable to render, please try loading this page with nbviewer.org.

In [18]:

# 테스트용으로 빼놓은 20% 의 요소를 집어넣어
# 예측값을 가져와 pred 변수에 저장 후 출력
pred = dtc.predict(X_test)
pred

Out[18]:

array([1, 1, 1, 1, 1, 1, 0, 1, 1, 0, 0, 1, 1, 1, 0, 0, 0, 1, 1, 1, 1, 1,
       0, 0, 0, 1, 1, 0, 0, 1, 1, 0, 0, 1, 1, 0, 1, 0, 0, 1, 1, 0, 1, 1,
       1, 0, 1, 1, 1, 0, 0, 1, 0, 0, 1, 1, 1, 1, 0, 1, 1, 0, 1, 1, 1, 1,
       1, 1, 1, 1, 1, 1, 1, 1, 0, 1, 1, 1, 1, 1, 1, 1, 1, 0, 1, 1, 1, 1,
       0, 1, 1, 0, 1, 1, 1, 1, 0, 0, 1, 0, 1, 1, 0, 1, 0, 1, 1, 1, 0, 0,
       1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 0, 1, 1], dtype=int64)

In [19]:

y_test

Out[19]:

75     0
278    1
512    1
217    1
154    1
      ..
573    0
503    0
120    1
352    1
230    1
Name: Loan_Status, Length: 123, dtype: int64

In [20]:

# score 함수를 사용하여
# 테스트 용 변수와 결과 값을 넣었을 때
# 정답률을 도출할 수 있음
dtc.score(X_test, y_test)

Out[20]:

0.7479674796747967

In [22]:

from sklearn.metrics import accuracy_score

# accuracy_score 를 사용해서 정답률을 확인할 수도 있다
accuracy_score(pred, y_test)

Out[22]:

0.7479674796747967

In [32]:

# 새로운 Dataset 을 가져옴
# 결과 값(대출 가능 여부)이 없는 데이터
# 이 데이터는 실제 학습된 머신에 데이터를 집어넣어 결과 값을 사용할 경우를
# 가정하고 가져온 데이터이다
# 고객의 정보를 기준으로 대출이 나올지 안나올지 확인해보기
df_test = pd.read_csv("../data_set/2.데이터 클린징/loan_test_cleaning.csv")
df_test.head(3)

Out[32]:

	Loan_ID	Gender	Married	Dependents	Education	Self_Employed	ApplicantIncome	CoapplicantIncome	LoanAmount	Loan_Amount_Term	Credit_History	Property_Area
0	0	1	1	0	0	0	5720	0	110.0	360.0	1.0	2
1	1	1	1	1	0	0	3076	1500	126.0	360.0	1.0	2
2	2	1	1	2	0	0	5000	1800	208.0	360.0	1.0	2

In [28]:

# Loan_ID 컬럼을 제외한 값이 X_test 에 저장된다
features = ['Gender', 'Married', 'Dependents', 'Education',
       'Self_Employed', 'ApplicantIncome', 'CoapplicantIncome', 'LoanAmount',
       'Loan_Amount_Term', 'Credit_History', 'Property_Area']
X_test = df_test[features]
X_test

Out[28]:

	Gender	Married	Dependents	Education	Self_Employed	ApplicantIncome	CoapplicantIncome	LoanAmount	Loan_Amount_Term	Credit_History	Property_Area
0	1	1	0	0	0	5720	0	110.0	360.0	1.0	2
1	1	1	1	0	0	3076	1500	126.0	360.0	1.0	2
2	1	1	2	0	0	5000	1800	208.0	360.0	1.0	2
3	1	1	2	0	0	2340	2546	100.0	360.0	1.0	2
4	1	0	0	1	0	3276	0	78.0	360.0	1.0	2
...	...	...	...	...	...	...	...	...	...	...	...
362	1	1	3	1	1	4009	1777	113.0	360.0	1.0	2
363	1	1	0	0	0	4158	709	115.0	360.0	1.0	2
364	1	0	0	0	0	3250	1993	126.0	360.0	1.0	1
365	1	1	0	0	0	5000	2393	158.0	360.0	1.0	0
366	1	0	0	0	1	9200	0	98.0	180.0	1.0	0

367 rows × 11 columns

In [30]:

# 예측 정답을 가져와서 처리한다
y_test = dtc.predict(X_test)
y_test

Out[30]:

array([0, 1, 1, 1, 1, 1, 1, 0, 1, 1, 1, 1, 1, 0, 0, 1, 0, 1, 0, 0, 1, 1,
       1, 1, 1, 1, 1, 1, 1, 1, 0, 1, 1, 0, 1, 0, 1, 1, 1, 1, 1, 1, 1, 1,
       1, 1, 1, 1, 0, 1, 1, 1, 1, 1, 1, 0, 1, 1, 0, 0, 1, 1, 1, 0, 1, 1,
       0, 0, 1, 0, 1, 0, 1, 0, 1, 0, 1, 1, 1, 1, 0, 0, 0, 1, 0, 0, 0, 1,
       0, 1, 1, 0, 0, 1, 0, 1, 1, 1, 1, 1, 1, 0, 1, 1, 1, 1, 0, 0, 1, 1,
       0, 1, 1, 1, 1, 1, 1, 0, 0, 0, 1, 1, 1, 0, 0, 0, 0, 1, 1, 1, 1, 1,
       1, 1, 1, 1, 0, 0, 1, 1, 0, 1, 0, 1, 0, 1, 1, 0, 0, 1, 1, 1, 1, 0,
       0, 1, 0, 0, 1, 1, 1, 0, 1, 1, 0, 0, 0, 1, 0, 1, 1, 0, 1, 0, 0, 0,
       1, 1, 0, 1, 1, 1, 0, 1, 0, 1, 1, 1, 0, 0, 0, 1, 0, 0, 1, 1, 0, 0,
       0, 1, 1, 1, 1, 1, 1, 1, 1, 1, 0, 1, 1, 0, 1, 1, 1, 1, 1, 0, 1, 1,
       1, 1, 1, 1, 0, 0, 1, 1, 1, 0, 1, 1, 0, 1, 1, 0, 0, 0, 1, 0, 1, 0,
       1, 0, 1, 0, 1, 1, 0, 1, 0, 1, 1, 1, 1, 0, 1, 1, 1, 1, 0, 1, 0, 1,
       0, 0, 0, 1, 0, 0, 1, 1, 1, 0, 0, 1, 0, 1, 0, 1, 1, 0, 1, 0, 0, 1,
       1, 1, 1, 1, 0, 1, 1, 0, 1, 1, 1, 0, 1, 1, 1, 0, 0, 0, 1, 1, 1, 1,
       1, 1, 1, 0, 1, 0, 1, 0, 0, 0, 1, 1, 1, 1, 1, 1, 1, 0, 1, 1, 1, 1,
       1, 1, 0, 1, 1, 1, 1, 1, 1, 0, 1, 1, 0, 1, 1, 1, 0, 1, 1, 1, 1, 1,
       1, 0, 0, 1, 1, 1, 0, 1, 1, 1, 1, 1, 1, 0, 1], dtype=int64)

In [33]:

# 결과 값을 다시 Dataset 에 넣었음
# 다수의 고객이 발생했다고 가정하면
# 결과 값을 한번에 도출하여 처리하기 때문에
# 해당 상황을 가정하고 test 진행하였음
df_test['Loan_Status'] = y_test
df_test

Out[33]:

	Loan_ID	Gender	Married	Dependents	Education	Self_Employed	ApplicantIncome	CoapplicantIncome	LoanAmount	Loan_Amount_Term	Credit_History	Property_Area	Loan_Status
0	0	1	1	0	0	0	5720	0	110.0	360.0	1.0	2	0
1	1	1	1	1	0	0	3076	1500	126.0	360.0	1.0	2	1
2	2	1	1	2	0	0	5000	1800	208.0	360.0	1.0	2	1
3	3	1	1	2	0	0	2340	2546	100.0	360.0	1.0	2	1
4	4	1	0	0	1	0	3276	0	78.0	360.0	1.0	2	1
...	...	...	...	...	...	...	...	...	...	...	...	...	...
362	362	1	1	3	1	1	4009	1777	113.0	360.0	1.0	2	1
363	363	1	1	0	0	0	4158	709	115.0	360.0	1.0	2	1
364	364	1	0	0	0	0	3250	1993	126.0	360.0	1.0	1	1
365	365	1	1	0	0	0	5000	2393	158.0	360.0	1.0	0	0
366	366	1	0	0	0	1	9200	0	98.0	180.0	1.0	0	1

367 rows × 13 columns

In [34]:

# 현재 유저의 상황을 user 라는 변수에 담아
# 예측 값을 출력하여 고객에게 전달
user = [[1,1,0,0,0,5720,0,110.0,360.0,1.0,2]]
dtc.predict(user)

C:\Users\user\anaconda3\Lib\site-packages\sklearn\base.py:439: UserWarning: X does not have valid feature names, but DecisionTreeClassifier was fitted with feature names
  warnings.warn(

Out[34]:

array([0], dtype=int64)

In [35]:

if dtc.predict(user)[0] == 1:
    print("대출이 가능")
else:
    print("은행에 문의하세요")

은행에 문의하세요

C:\Users\user\anaconda3\Lib\site-packages\sklearn\base.py:439: UserWarning: X does not have valid feature names, but DecisionTreeClassifier was fitted with feature names
  warnings.warn(